5q^2+32q+35=23

Solution for 5q^2+32q+35=23 equation:

Simplifying
5q2 + 32q + 35 = 23

Reorder the terms:
35 + 32q + 5q2 = 23

Solving
35 + 32q + 5q2 = 23

Solving for variable 'q'.

Reorder the terms:
35 + -23 + 32q + 5q2 = 23 + -23

Combine like terms: 35 + -23 = 12
12 + 32q + 5q2 = 23 + -23

Combine like terms: 23 + -23 = 0
12 + 32q + 5q2 = 0

Factor a trinomial.
(6 + q)(2 + 5q) = 0

Subproblem 1
Set the factor '(6 + q)' equal to zero and attempt to solve:

Simplifying
6 + q = 0

Solving
6 + q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + q = 0 + -6

Combine like terms: 6 + -6 = 0
0 + q = 0 + -6
q = 0 + -6

Combine like terms: 0 + -6 = -6
q = -6

Simplifying
q = -6
Subproblem 2
Set the factor '(2 + 5q)' equal to zero and attempt to solve:

Simplifying
2 + 5q = 0

Solving
2 + 5q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5q = 0 + -2
5q = 0 + -2

Combine like terms: 0 + -2 = -2
5q = -2

Divide each side by '5'.
q = -0.4

Simplifying
q = -0.4
Solution
q = {-6, -0.4}